In a B+ tree, if the search-key value is 8 bytes long, the block size is 512 bytes and the block pointer size is 2 bytes, then the maximum order of the B+ tree is ________.

The order $p$ of a B+ tree is defined as the maximum number of child (block) pointers an internal node can hold.

An internal node of order $p$ contains at most $p$ block pointers and $(p - 1)$ search keys. Therefore, the node size constraint is:

Given:

• Block pointer size $= 2$ bytes

• Search-key size $= 8$ bytes

• Block size $= 512$ bytes

Substitute the given values:

Thus, the maximum order of the B+ tree is 52.