Consider a relational schema $team(name, city, owner)$, with functional dependencies $\{name \rightarrow city, name \rightarrow owner\}$. The relation $team$ is decomposed into two relations, $t1(name, city)$ and $t2(name, owner)$. Which of the following statement(s) is/are TRUE?

Let us analyze the given relational schema and functional dependencies:

1. Candidate Key of $team(name, city, owner)$:

   $$\{name\}^+ = \{name, city, owner\}$$

   Since $name$ determines all attributes of the schema, $name$ is the candidate key (and superkey).

2. Normal Form of $team$: For both functional dependencies $name \rightarrow city$ and $name \rightarrow owner$, the left-hand side ($name$) is a superkey. Therefore, the relation $team$ is in BCNF (and consequently in 3NF, 2NF, and 1NF). Hence, statements (A) and (D) are FALSE.

3. Normal Form of $t1(name, city)$ and $t2(name, owner)$:

   • For $t1(name, city)$, the projected functional dependency is $name \rightarrow city$, where $name$ is the candidate key. Thus, $t1$ is in BCNF.

   • For $t2(name, owner)$, the projected functional dependency is $name \rightarrow owner$, where $name$ is the candidate key. Thus, $t2$ is in BCNF.

   Hence, statement (B) is TRUE.

4. Lossless Join Check:

   $$R_1 \cap R_2 = \{name, city\} \cap \{name, owner\} = \{name\}$$

   $$\{name\}^+ = \{name, city, owner\}$$

   Since $R_1 \cap R_2 \rightarrow R_1$ (and also $R_1 \cap R_2 \rightarrow R_2$), the common attribute is a candidate key for both decomposed relations. Thus, the decomposition is lossless. Hence, statement (C) is TRUE.

Therefore, the correct statements are B and C.