In an IPv4 datagram, the M bit is 0, the value of HLEN is 10, the value of total length is 400 and the fragment offset value is 300. The position of the datagram, the sequence numbers of the first and the last bytes of the payload, respectively are

Let us analyze the given parameters of the IPv4 datagram:

1. Position of the Datagram:

   • $\text{MF (More Fragments bit)} = 0$.

   • An offset value of $300 > 0$ with $\text{MF} = 0$ signifies that this is the Last fragment.

2. Header Length and Payload Length:

   • $\text{Header Length (in bytes)} = \text{HLEN} \times 4 = 10 \times 4 = 40\text{ bytes}$.

   • $\text{Total Length} = 400\text{ bytes}$.

   • $\text{Payload Length} = \text{Total Length} - \text{Header Length} = 400 - 40 = 360\text{ bytes}$.

3. Byte Sequence Numbers:

   • The fragment offset is measured in units of $8\text{ bytes}$.

   • First byte number of the payload $= \text{Offset} \times 8 = 300 \times 8 = 2400$.

   • Last byte number of the payload $= \text{First byte} + \text{Payload Length} - 1 = 2400 + 360 - 1 = 2759$.

Thus, the datagram is the Last fragment, with payload byte range 2400 to 2759 (Option C).