Consider two hosts $X$ and $Y$, connected by a single direct link of rate $10^6$ bits/sec. The distance between the two hosts is $10,000$ km and the propagation speed along the link is $2 \times 10^8$ m/sec. Host $X$ sends a file of $50,000$ bytes as one large message to host $Y$ continuously. Let the transmission and propagation delays be $p$ milliseconds and $q$ milliseconds, respectively. Then the values of $p$ and $q$ are

Given parameters:

• Bandwidth (Transmission rate), $B = 10^6\text{ bits/sec}$

• Distance, $D = 10,000\text{ km} = 10^7\text{ m}$

• Propagation speed, $v = 2 \times 10^8\text{ m/sec}$

• Message size, $L = 50,000\text{ bytes} = 50,000 \times 8\text{ bits} = 400,000\text{ bits} = 4 \times 10^5\text{ bits}$

1. Transmission Delay ($p$):

   $$p = \frac{L}{B} = \frac{4 \times 10^5\text{ bits}}{10^6\text{ bits/sec}} = 0.4\text{ seconds} = 400\text{ ms}$$

2. Propagation Delay ($q$):

   $$q = \frac{D}{v} = \frac{10^7\text{ m}}{2 \times 10^8\text{ m/sec}} = 0.05\text{ seconds} = 50\text{ ms}$$

Thus, $p = 400$ and $q = 50$, which matches option (D).