Which one of the following is NOT a valid identity?
Topic-wise GATE CS PYQs with verified steps
GATE CSE 2019 · Q6
Time
Select one answerSingle correct
Solution
Official answer: B) (x + y) ⊕ z = x ⊕ (y + z)
Boolean Algebra and MinimizationLet us examine each option:
Option A: XOR is associative, so is a valid identity.
Option B: is not valid. For example, let , , :
Since , this is not a valid identity.
Option C: . If , then . Thus, this is valid.
Option D: is the standard XNOR expression. The complement of XNOR is XOR, so , which is valid.
Therefore, B is NOT a valid identity.
Try the question first, then check your work.
Examiner trap
Test small truth table values (e.g., ) to check if the distributive-like property holds between OR and XOR.
This Boolean Algebra and Minimization previous year question is Q6 of the GATE CSE 2019 paper. Find more GATE CSE PYQs on Boolean Algebra and Minimization in Digital Logic, or browse all GATE CSE PYQs.
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Boolean Algebra and Minimization has 36 GATE CSE PYQs across 23 papers from 2011 to 2026. 13 of them are 1-mark MCQs like this one, and it is the only one in GATE CSE 2019.
How GATE tests Boolean Algebra and MinimizationIndependent practice explanation verified by the GateAI team. GATE is conducted by the IITs; question text follows the official paper.