Consider the following expression. $$\lim_{x \to -3} \frac{\sqrt{2x+22}-4}{x+3}$$ The value of the above expression (rounded to 2 decimal places) is ________.

Evaluating the limit directly by substituting $x = -3$ gives an indeterminate form of $\frac{0}{0}$:

Applying L'Hôpital's Rule, we differentiate the numerator and the denominator with respect to $x$:

Substituting $x = -3$:

Thus, the value of the expression is 0.25.