The value of the expression $13^{99} \pmod{17}$, in the range 0 to 16, is _______.

By Fermat's Little Theorem, if $p$ is prime and $\gcd(a, p) = 1$, then:

Here, $a = 13$ and $p = 17$ (which is prime). Thus:

We can decompose the exponent $99$ as:

Therefore:

Since $13 \equiv -4 \pmod{17}$:

Now, reducing $-64$ modulo $17$:

Thus, the value of the expression in the range 0 to 16 is 4.