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Probability and Statistics

GATE CSE 2017 Set 2 · Q31

MCQ2 marksMedium

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For any discrete random variable XX, with probability mass function P(X=j)=pjP(X = j) = p_j, pj≥0p_j \ge 0, j∈{0,…,N}j \in \{0, \dots, N\}, and ∑j=0Npj=1\sum_{j=0}^N p_j = 1, define the polynomial function gX(z)=∑j=0Npjzjg_X(z) = \sum_{j=0}^N p_j z^j. For a certain discrete random variable YY, there exists a scalar β∈[0,1]\beta \in [0, 1] such that gY(z)=(1−β+βz)Ng_Y(z) = (1 - \beta + \beta z)^N. The expectation of YY is

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Solution

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Official answer: B) N

Probability and Statistics

The polynomial function gX(z)=∑j=0Npjzj=E[zX]g_X(z) = \sum_{j=0}^N p_j z^j = E[z^X] is the probability generating function (PGF) of the random variable XX.

The expectation E[Y]E[Y] can be computed by taking the first derivative of gY(z)g_Y(z) with respect to zz and evaluating at z=1z = 1:

E[Y]=gY′(1)E[Y] = g_Y^{\prime}(1)

Given:

gY(z)=(1−β+βz)Ng_Y(z) = (1 - \beta + \beta z)^N

Differentiating with respect to zz using the chain rule:

gY′(z)=N(1−β+βz)N−1⋅βg_Y^{\prime}(z) = N(1 - \beta + \beta z)^{N-1} \cdot \beta

Evaluating at z=1z = 1:

gY′(1)=N(1−β+β(1))N−1⋅β=N(1)N−1β=Nβg_Y^{\prime}(1) = N(1 - \beta + \beta(1))^{N-1} \cdot \beta = N(1)^{N-1} \beta = N\beta

Alternatively, recognizing gY(z)=((1−β)+βz)Ng_Y(z) = ((1-\beta) + \beta z)^N as the PGF of a Binomial distribution Y∼Binomial(N,β)Y \sim \text{Binomial}(N, \beta), the mean is known to be E[Y]=NβE[Y] = N\beta.

Hence, the correct option is (B).

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This Probability and Statistics previous year question is Q31 of the GATE CSE 2017 Set 2 paper. Find more GATE CSE PYQs on Probability and Statistics in Engineering Mathematics, or browse all GATE CSE PYQs.

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GateAI solution cardGATE CSE 2017 Set 2 · Q31 · MCQ

For any discrete random variable X, with probability mass function P(X = j) = pj, pj ≥ 0, j ∈ {0, , N}, and Σj=0N pj = 1, define the polynomial function gX(z) = Σj=0N pj zj. For a certain discrete random variable Y, there exists a scalar ∈ [0, 1] such that gY(z) = (1 - + z)N. The expectation of Y is

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Independent practice explanation verified by the GateAI team. GATE is conducted by the IITs; question text follows the official paper.