Initial volume of pure spirit, V=10 litres.
Volume replaced each time, x=1 litre.
Total number of replacement operations, n=3 (initial replacement, subsequently once, and repeated one more time).
The formula for the quantity of pure liquid remaining after n successive operations is:
Remaining spirit=V(1−Vx)n Substitute the values:
Remaining spirit=10(1−101)3=10×(0.9)3=10×0.729=7.29 litres Hence, the correct option is (D).