Given the sequence of terms, AD CG FK JP, the next term is
Topic-wise GATE CS PYQs with verified steps
GATE CSE 2012 · Q65
Time
Select one answerSingle correct
Solution
Official answer: A) OV
Quantitative AptitudeLet us analyze the letters by their alphabetical positions (A = 1, B = 2, ..., Z = 26):
First letters:
A (1)
C (3):
F (6):
J (10):
Next first letter: , which corresponds to O.
Second letters:
D (4)
G (7):
K (11):
P (16):
Next second letter: , which corresponds to V.
Combining the two letters gives OV, which corresponds to option (A).
Try the question first, then check your work.
Examiner trap
Analyze the progression of the numerical positions in the alphabet for the first and second letters separately.
This Quantitative Aptitude previous year question is Q65 of the GATE CSE 2012 paper. Find more GATE CSE PYQs on Quantitative Aptitude in General Aptitude, or browse all GATE CSE PYQs.
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Quantitative Aptitude has 53 GATE CSE PYQs across 13 papers from 2011 to 2026. 27 of them are 2-mark MCQs like this one, and GATE CSE 2012 has 5.
How GATE tests Quantitative AptitudeIndependent practice explanation verified by the GateAI team. GATE is conducted by the IITs; question text follows the official paper.