We have 10 processes with arrival times (AT) and burst times (BT):
Actuators (A): BT=6 s at AT=10,20,30,40,50
Controllers (C): BT=8 s at AT=11,22,33,44,55
Sorting all processes by arrival time in FCFS order:
A1: AT=10, BT=6
C1: AT=11, BT=8
A2: AT=20, BT=6
C2: AT=22, BT=8
A3: AT=30, BT=6
C3: AT=33, BT=8
A4: AT=40, BT=6
C4: AT=44, BT=8
A5: AT=50, BT=6
C5: AT=55, BT=8
Now, let's schedule them with FCFS and compute Start Time (ST), Completion Time (CT), and Waiting Time (WT=ST−AT):
| Process | AT | BT | ST | CT | WT=ST−AT |
|---|
| A1 | 10 | 6 | 10 | 16 | 10−10=0 |
| C1 | 11 | 8 | 16 | 24 | 16−11=5 |
| A2 | 20 | 6 | 24 | 30 | 24−20=4 |
| C2 | 22 | 8 | 30 | 38 | 30−22=8 |
| A3 | 30 | 6 | 38 | 44 | 38−30=8 |
| C3 | 33 | 8 | 44 | 52 | 44−33=11 |
| A4 | 40 | 6 | 52 | 58 | 52−40=12 |
| C4 | 44 | 8 | 58 | 66 | 58−44=14 |
| A5 | 50 | 6 | 66 | 72 | 66−50=16 |
| C5 | 55 | 8 | 72 | 80 | 72−55=17 |
Total Waiting Time:
∑WT=0+5+4+8+8+11+12+14+16+17=95 seconds Average Waiting Time:
Average WT=1095=9.5 seconds