Consider a disk pack with a seek time of 4 milliseconds and rotational speed of 10000 rotations per minute (RPM). It has 600 sectors per track and each sector can store 512 bytes of data. Consider a file stored in the disk. The file contains 2000 sectors. Assume that every sector access necessitates a seek, and the average rotational latency for accessing each sector is half of the time for one complete rotation. The total time (in milliseconds) needed to read the entire file is _________.

Given parameters:

• Seek time per sector access = $4\text{ ms}$

• Rotational speed = $10000\text{ RPM}$

• Sectors per track = $600$

• File size = $2000\text{ sectors}$

### Step 1: Calculate the time for one complete rotation

### Step 2: Calculate rotational latency and transfer time per sector

• Average rotational latency = $\frac{1}{2} \times 6\text{ ms} = 3\text{ ms}$

• Transfer time for 1 sector = $\frac{\text{Time for 1 rotation}}{\text{Sectors per track}} = \frac{6\text{ ms}}{600} = 0.01\text{ ms}$

### Step 3: Total access time per sector

### Step 4: Total time to read 2000 sectors