Consider the following function implemented in C:void printxy(int x, int y) { int *ptr; x = 0; ptr = &x; y = *ptr; *ptr = 1; printf("%d,%d",x,y); }The output of invoking printxy(1,1) is

Let's trace the execution of printxy(1, 1) step by step:

1. Initial values of parameters: $x = 1$, $y = 1$.

2. x = 0; $\implies x$ becomes $0$.

3. ptr = &x; $\implies ptr$ points to the memory location of $x$.

4. y = *ptr; $\implies y$ is assigned the value stored at ptr (which is $x = 0$), so $y = 0$.

5. *ptr = 1; $\implies$ the value at the address ptr is updated to $1$. Since ptr points to $x$, $x$ becomes $1$.

6. printf("%d,%d", x, y); prints the current values of $x$ and $y$, which are $1$ and $0$ respectively.

Thus, the output printed is 1,0, corresponding to option (C).