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Turing Machines and Undecidability

GATE CSE 2014 Set 1 · Q35

MCQ2 marksEasy

Time

Let LL be a language and Lˉ\bar{L} be its complement. Which one of the following is NOT a viable possibility?

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Solution

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Official answer: C) Both L and L are r.e. but not recursive.

Turing Machines and Undecidability

A fundamental theorem in computability theory states that a language LL is recursive (decidable) if and only if both LL and its complement Lˉ\bar{L} are recursively enumerable (r.e.).

From this theorem, the possible relationships between LL and Lˉ\bar{L} are:

  1. Both LL and Lˉ\bar{L} are recursive (and hence both are r.e.).

  2. One of LL or Lˉ\bar{L} is r.e. but not recursive; the other must NOT be r.e.

  3. Neither LL nor Lˉ\bar{L} is r.e.

It is impossible for both LL and Lˉ\bar{L} to be r.e. without both being recursive. Therefore, option C is NOT a viable possibility.

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This Turing Machines and Undecidability previous year question is Q35 of the GATE CSE 2014 Set 1 paper. Find more GATE CSE PYQs on Turing Machines and Undecidability in Theory of Computation, or browse all GATE CSE PYQs.

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Turing Machines and Undecidability in GATE CSE

Turing Machines and Undecidability has 30 GATE CSE PYQs across 20 papers from 2012 to 2026. 13 of them are 2-mark MCQs like this one, and GATE CSE 2014 Set 1 has 2.

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GateAI solution cardGATE CSE 2014 Set 1 · Q35 · MCQ

Let L be a language and L be its complement. Which one of the following is NOT a viable possibility?

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Independent practice explanation verified by the GateAI team. GATE is conducted by the IITs; question text follows the official paper.