A canonical set of items is given below $$S \rightarrow L. > R$$ $$Q \rightarrow R.$$ On input symbol < the set has

In the given canonical set of LR items:

1. $S \rightarrow L. > R$

   • The dot is followed by the terminal symbol $>$. A shift action can only occur on the input symbol $>$, not on $<$.

2. $Q \rightarrow R.$

   • This is a completed reduce item. A reduction to $Q$ might be placed in the lookahead set (or $\text{FOLLOW}(Q)$ for SLR), but for a conflict to occur:

     • A shift-reduce conflict requires both a shift action and a reduce action on the *same* input symbol.

     • A reduce-reduce conflict requires two different reduction actions on the *same* input symbol.

On the input symbol $<$:

• There is no shift action because the shift item only shifts on symbol $> $.

• There is at most one reduce action (from $Q \rightarrow R.$), so there is no reduce-reduce conflict.

• Since there is no shift action on $<$, there is no shift-reduce conflict.

Therefore, on input symbol $<$, the set has neither a shift-reduce nor a reduce-reduce conflict (Option D).