Relation $R$ has eight attributes $ABCDEFGH$. Fields of $R$ contain only atomic values. $F=\{CH\rightarrow G, A\rightarrow BC, B\rightarrow CFH, E\rightarrow A, F\rightarrow EG\}$ is a set of functional dependencies (FDs) so that $F^+$ is exactly the set of FDs that hold for $R$. The relation $R$ is

1. Candidate Keys: From Q.54, the candidate keys are $AD, BD, ED, FD$.

2. Prime and Non-Prime Attributes:

   • Prime attributes (attributes belonging to any candidate key): $\{A, B, D, E, F\}$.

   • Non-prime attributes: $\{C, G, H\}$.

3. 1NF Check:

   • The fields of $R$ contain only atomic values, so $R$ is in 1NF.

4. 2NF Check:

   • A relation is in 2NF if no non-prime attribute is partially dependent on any candidate key.

   • Consider the FD $A \rightarrow BC$: $A$ is a proper subset of the candidate key $AD$, and $C$ is a non-prime attribute. Thus, $A \rightarrow C$ represents a partial dependency.

   • Similarly, in $B \rightarrow CFH$, $B$ is a proper subset of $BD$, and $C, H$ are non-prime attributes.

   • Since partial dependencies exist, the relation is not in 2NF.

Therefore, the relation $R$ is in 1NF, but not in 2NF.

Hence, the correct option is (A).