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Quantitative Aptitude

GATE CSE 2013 · Q58

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What will be the maximum sum of 44,42,40,…44, 42, 40, \dots ?

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Solution

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Official answer: C) 506

Quantitative Aptitude

The given sequence is an Arithmetic Progression (AP) where:

  • First term, a=44a = 44

  • Common difference, d=42−44=−2d = 42 - 44 = -2

To maximize the sum, we must include all positive terms (and optionally zero, which does not alter the sum).

Find the number of positive terms nn:

an≥0  ⟹  44+(n−1)(−2)≥0a_n \ge 0 \implies 44 + (n - 1)(-2) \ge 0
44−2n+2≥0  ⟹  2n≤46  ⟹  n≤2344 - 2n + 2 \ge 0 \implies 2n \le 46 \implies n \le 23
  • The 22nd22^{\text{nd}} term is a22=44+(22−1)(−2)=2a_{22} = 44 + (22 - 1)(-2) = 2.

  • The 23rd23^{\text{rd}} term is a23=44+(23−1)(−2)=0a_{23} = 44 + (23 - 1)(-2) = 0.

Sum of the first n=22n = 22 (or n=23n = 23) terms:

Sn=n2[2a+(n−1)d]S_n = \frac{n}{2}[2a + (n-1)d]
S23=232[2(44)+22(−2)]=232[88−44]=232×44=23×22=506S_{23} = \frac{23}{2}[2(44) + 22(-2)] = \frac{23}{2}[88 - 44] = \frac{23}{2} \times 44 = 23 \times 22 = 506

Thus, the maximum sum is 506 (Option C).

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This Quantitative Aptitude previous year question is Q58 of the GATE CSE 2013 paper. Find more GATE CSE PYQs on Quantitative Aptitude in General Aptitude, or browse all GATE CSE PYQs.

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What will be the maximum sum of 44, 42, 40, ?

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