Given the following Karnaugh Map for a Boolean function $F(w, x, y, z)$: Which one or more of the following Boolean expression(s) represent(s) $F$?

From the given 4-variable Karnaugh Map with row variables $wx$ and column variables $yz$:

• The $1$s are located at the four corners: $(w,x,y,z) \in \{(0,0,0,0), (0,0,1,0), (1,0,0,0), (1,0,1,0)\}$, which corresponds to the minterms $m_0, m_2, m_8, m_{10}$. Combining these four corner cells gives the term $\bar{x}\bar{z}$.

• The $1$s are also located in the central $2 \times 2$ block: rows $01, 11$ ($x = 1$) and columns $01, 11$ ($z = 1$), corresponding to minterms $m_5, m_7, m_{13}, m_{15}$. Combining these four cells gives the term $xz$.

Thus, the minimal sum-of-products (SOP) expression for the function is:

This directly matches Option (D).

Now, let us evaluate the other options:

• Option (A):

  $$\bar{w}\bar{x}y\bar{z} + w\bar{x}y\bar{z} + \bar{w}\bar{x}\bar{y}\bar{z} + w\bar{x}\bar{y}\bar{z} + xz$$

  Combining the first four product terms:

  $$\bar{x}y\bar{z}(\bar{w} + w) + \bar{x}\bar{y}\bar{z}(\bar{w} + w) = \bar{x}y\bar{z} + \bar{x}\bar{y}\bar{z} = \bar{x}\bar{z}(y + \bar{y}) = \bar{x}\bar{z}$$

  Thus, the expression simplifies to $\bar{x}\bar{z} + xz = F$. Therefore, Option (A) is correct.

• Option (B): Contains the term $w\bar{x}yz$ (minterm $m_{11}$), where the K-map has a value of $0$. Hence, Option (B) is incorrect.

• Option (C): Contains the term $w\bar{x}\bar{y}z$ (minterm $m_9$), where the K-map has a value of $0$. Hence, Option (C) is incorrect.

Therefore, the correct options are A and D.