Let f(x)=0.75x3−2x2−2x+4=43x3−2x2−2x+4.
The derivative is:
f′(x)=2.25x2−4x−2=49x2−4x−2 The Newton-Raphson iteration formula is:
xn+1=xn−f′(xn)f(xn) Iteration 1:
For x0=2:
f(2)=0.75(8)−2(4)−2(2)+4=6−8−4+4=−2 f′(2)=2.25(4)−4(2)−2=9−8−2=−1 x1=2−−1−2=2−2=0 Iteration 2:
For x1=0:
f′(0)=−2 x2=0−−24=0−(−2)=2 Iteration 3:
Since x2=x0=2, we get:
x3=x1=0 Thus, statement (I) is TRUE as x3=0.
Statement (II) is FALSE because the sequence oscillates endlessly between 2 and 0 (2,0,2,0,…) and never converges to a root.
Therefore, only statement I is true.