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Linear Algebra

GATE CSE 2021 Set 2 · Q24

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Suppose that PP is a 4×54 \times 5 matrix such that every solution of the equation Px=0Px = 0 is a scalar multiple of [2  5  4  3  1]T[2\; 5\; 4\; 3\; 1]^T. The rank of PP is _______.

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Official answer: 4 (±0)

Linear Algebra

According to the Rank-Nullity Theorem, for any matrix PP with nn columns:

Rank(P)+Nullity(P)=n\text{Rank}(P) + \text{Nullity}(P) = n

Here, PP is a 4×54 \times 5 matrix, so the number of columns is n=5n = 5.

The null space of PP is the set of all vectors xx satisfying Px=0Px = 0. Since every solution is a scalar multiple of the single non-zero vector [2  5  4  3  1]T[2\; 5\; 4\; 3\; 1]^T, the null space has dimension 11:

Nullity(P)=1\text{Nullity}(P) = 1

Applying the Rank-Nullity Theorem:

Rank(P)=5−1=4\text{Rank}(P) = 5 - 1 = 4

Thus, the rank of PP is 4.

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This Linear Algebra previous year question is Q24 of the GATE CSE 2021 Set 2 paper. Find more GATE CSE PYQs on Linear Algebra in Engineering Mathematics, or browse all GATE CSE PYQs.

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Linear Algebra in GATE CSE

Linear Algebra has 46 GATE CSE PYQs across 26 papers from 2011 to 2026. 13 of them are 1-mark NAT questions like this one, and GATE CSE 2021 Set 2 has 2.

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Suppose that P is a 4 × 5 matrix such that every solution of the equation Px = 0 is a scalar multiple of [2 5 4 3 1]T. The rank of P is …

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