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Sets, Relations, Lattices and Groups

GATE CSE 2024 Set 1 · Q52

MSQ2 marksEasy

Time

Consider the operators ◊\Diamond and □\square defined by a◊b=a+2ba \Diamond b = a + 2b, a□b=aba \square b = ab, for positive integers. Which of the following statements is/are TRUE?

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Official answer: B) Operator obeys the associative law; D) Operator over the operator obeys the distributive law

Sets, Relations, Lattices and Groups

Let the two binary operations on positive integers be:

a◊b=a+2ba \Diamond b = a + 2b
a□b=aba \square b = ab

Let us evaluate each statement:

  • Option (A): Associativity of ◊\Diamond requires (a◊b)◊c=a◊(b◊c)(a \Diamond b) \Diamond c = a \Diamond (b \Diamond c).

    (a◊b)◊c=(a+2b)◊c=(a+2b)+2c=a+2b+2c(a \Diamond b) \Diamond c = (a + 2b) \Diamond c = (a + 2b) + 2c = a + 2b + 2c
    a◊(b◊c)=a◊(b+2c)=a+2(b+2c)=a+2b+4ca \Diamond (b \Diamond c) = a \Diamond (b + 2c) = a + 2(b + 2c) = a + 2b + 4c

    Since $a + 2b + 2c

e a + 2b + 4cforpositiveintegers, for positive integers, \Diamond$ is not associative. Thus, (A) is FALSE.

  • Option (B): Associativity of □\square requires (a□b)□c=a□(b□c)(a \square b) \square c = a \square (b \square c).

    (a□b)□c=(ab)□c=(ab)c=abc(a \square b) \square c = (ab) \square c = (ab)c = abc
    a□(b□c)=a□(bc)=a(bc)=abca \square (b \square c) = a \square (bc) = a(bc) = abc

    Since multiplication is associative, (a□b)□c=a□(b□c)(a \square b) \square c = a \square (b \square c). Thus, (B) is TRUE.

  • Option (C): Distributivity of ◊\Diamond over □\square requires a◊(b□c)=(a◊b)□(a◊c)a \Diamond (b \square c) = (a \Diamond b) \square (a \Diamond c).

    LHS=a◊(bc)=a+2bc\text{LHS} = a \Diamond (bc) = a + 2bc
    RHS=(a◊b)□(a◊c)=(a+2b)(a+2c)=a2+2ac+2ab+4bc\text{RHS} = (a \Diamond b) \square (a \Diamond c) = (a + 2b)(a + 2c) = a^2 + 2ac + 2ab + 4bc

    Since $LHS\text{LHS}

e RHS\text{RHS}$ in general, (C) is FALSE.

  • Option (D): Distributivity of □\square over ◊\Diamond requires a□(b◊c)=(a□b)◊(a□c)a \square (b \Diamond c) = (a \square b) \Diamond (a \square c).

    LHS=a□(b+2c)=a(b+2c)=ab+2ac\text{LHS} = a \square (b + 2c) = a(b + 2c) = ab + 2ac
    RHS=(ab)◊(ac)=ab+2(ac)=ab+2ac\text{RHS} = (ab) \Diamond (ac) = ab + 2(ac) = ab + 2ac

    Since LHS=RHS\text{LHS} = \text{RHS}, □\square distributes over ◊\Diamond. Thus, (D) is TRUE.

Therefore, the correct statements are B and D.

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This Sets, Relations, Lattices and Groups previous year question is Q52 of the GATE CSE 2024 Set 1 paper. Find more GATE CSE PYQs on Sets, Relations, Lattices and Groups in Engineering Mathematics, or browse all GATE CSE PYQs.

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Sets, Relations, Lattices and Groups has 11 GATE CSE PYQs across 9 papers from 2014 to 2025. 3 of them are 2-mark MSQs like this one, and it is the only one in GATE CSE 2024 Set 1.

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GateAI solution cardGATE CSE 2024 Set 1 · Q52 · MSQ

Consider the operators and defined by a b = a + 2b, a b = ab, for positive integers. Which of the following statements is/are TRUE?

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