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Analytical Aptitude

GATE CSE 2024 Set 2 · Q10

MCQ2 marksEasy

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In the 4×44 \times 4 array shown below, each cell of the first three rows has either a cross (X) or a number. The number in a cell represents the count of the immediate neighboring cells (left, right, top, bottom, diagonals) NOT having a cross (X). Given that the last row has no crosses (X), the sum of the four numbers to be filled in the last row is

GATE CSE 2024 Set 2 Q10 diagram

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Solution

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Official answer: A) 11

Analytical Aptitude

Let the 4 cells in the fourth (last) row from left to right be denoted as c1,c2,c3,c4c_1, c_2, c_3, c_4.

We are given that no cell in the fourth row contains a cross (X). Therefore, all neighbors within row 4 do not have crosses.

Let us calculate the count of immediate non-cross neighbors for each cell in row 4:

  1. Cell c1c_1 (row 4, column 1):

    • Neighboring cells: (3,1)(3,1), (3,2)(3,2), and (4,2)(4,2). (Total = 3 neighbors)

    • Non-cross neighbors: (3,1)(3,1) which is 33, and (4,2)(4,2) which is a number.

    • Cross neighbor: (3,2)(3,2) which is X\text{X}.

    • Value of c1=2c_1 = 2.

  2. Cell c2c_2 (row 4, column 2):

    • Neighboring cells: (3,1)(3,1), (3,2)(3,2), (3,3)(3,3), (4,1)(4,1), and (4,3)(4,3). (Total = 5 neighbors)

    • Non-cross neighbors: (3,1)(3,1), (3,3)(3,3), (4,1)(4,1), and (4,3)(4,3).

    • Cross neighbor: (3,2)(3,2) which is X\text{X}.

    • Value of c2=5−1=4c_2 = 5 - 1 = 4.

  3. Cell c3c_3 (row 4, column 3):

    • Neighboring cells: (3,2)(3,2), (3,3)(3,3), (3,4)(3,4), (4,2)(4,2), and (4,4)(4,4). (Total = 5 neighbors)

    • Non-cross neighbors: (3,3)(3,3), (4,2)(4,2), and (4,4)(4,4).

    • Cross neighbors: (3,2)(3,2) which is X\text{X}, and (3,4)(3,4) which is X\text{X}.

    • Value of c3=5−2=3c_3 = 5 - 2 = 3.

  4. Cell c4c_4 (row 4, column 4):

    • Neighboring cells: (3,3)(3,3), (3,4)(3,4), and (4,3)(4,3). (Total = 3 neighbors)

    • Non-cross neighbors: (3,3)(3,3) and (4,3)(4,3).

    • Cross neighbor: (3,4)(3,4) which is X\text{X}.

    • Value of c4=3−1=2c_4 = 3 - 1 = 2.

Sum of the four numbers filled in the last row:

Sum=c1+c2+c3+c4=2+4+3+2=11\text{Sum} = c_1 + c_2 + c_3 + c_4 = 2 + 4 + 3 + 2 = 11

Thus, option (A) is correct.

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This Analytical Aptitude previous year question is Q10 of the GATE CSE 2024 Set 2 paper. Find more GATE CSE PYQs on Analytical Aptitude in General Aptitude, or browse all GATE CSE PYQs.

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Analytical Aptitude has 11 GATE CSE PYQs across 8 papers from 2017 to 2026. 7 of them are 2-mark MCQs like this one, and it is the only one in GATE CSE 2024 Set 2.

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GateAI solution cardGATE CSE 2024 Set 2 · Q10 · MCQ

In the 4 × 4 array shown below, each cell of the first three rows has either a cross (X) or a number. The number in a cell represents the count of the immediate neighboring cells (left, right, top, bottom, diagonals) NOT having a cross (X). Given that the last row has no crosses (X), the sum of the four numbers to be filled in the last row is

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Independent practice explanation verified by the GateAI team. GATE is conducted by the IITs; question text follows the official paper.