Let (x,y) denote the outcome of the two rolls, where x is the number on the first roll and y is the number on the second roll.
The total number of possible outcomes when rolling a six-faced die twice is:
n(S)=6×6=36 We need to find the number of favorable outcomes where y is an integer multiple of x (y=kx for some positive integer k):
For x=1: y∈{1,2,3,4,5,6}⟹6 outcomes
For x=2: y∈{2,4,6}⟹3 outcomes
For x=3: y∈{3,6}⟹2 outcomes
For x=4: y∈{4}⟹1 outcome
For x=5: y∈{5}⟹1 outcome
For x=6: y∈{6}⟹1 outcome
Total number of favorable outcomes:
n(E)=6+3+2+1+1+1=14 Therefore, the required probability is:
P(E)=n(S)n(E)=3614=187 Hence, the correct option is C.