Consider a memory management system that uses a page size of 2 KB. Assume that both the physical and virtual addresses start from 0. Assume that the pages 0, 1, 2, and 3 are stored in the page frames 1, 3, 2, and 0, respectively. The physical address (in decimal format) corresponding to the virtual address 2500 (in decimal format) is ________

Determine the page size:

Break down the virtual address $2500$:

• Virtual Page Number (VPN) = $\lfloor 2500 / 2048 \rfloor = 1$

• Page Offset = $2500 \bmod 2048 = 2500 - 2048 = 452$

Map the virtual page to its physical frame: According to the page mapping:

• Page 0 $\to$ Frame 1

• Page 1 $\to$ Frame 3

• Page 2 $\to$ Frame 2

• Page 3 $\to$ Frame 0

Therefore, Page 1 is mapped to Frame 3.

Calculate the physical address: