What does the following fragment of C program print?Char c[] = "GATE2011"; char *p = c; printf("%s", p + p[3] - p[1]);

Let us trace the execution step by step:

1. The character array c is initialized with the string "GATE2011":

   • c[0] = 'G'

   • c[1] = 'A'

   • c[2] = 'T'

   • c[3] = 'E'

   • c[4] = '2'

   • c[5] = '0'

   • c[6] = '1'

   • c[7] = '1'

   • c[8] = '\0'

2. Pointer p points to the beginning of the array c (i.e., p = c).

3. Evaluate p[3] and p[1]:

   • p[3] is the character 'E', whose ASCII value is $69$.

   • p[1] is the character 'A', whose ASCII value is $65$.

4. Compute the offset:

   $$p[3] - p[1] = 69 - 65 = 4$$

5. The pointer passed to printf("%s", ...) is p + 4, which points to the subarray starting at index 4 (c[4]), containing "2011".

6. Therefore, printf prints the string starting from c[4], which is 2011.

Hence, option (C) is correct.