Consider the following C program.#include<stdio.h> int main( ) { static int a[ ] = {10, 20, 30, 40, 50}; static int *p[ ] = {a, a+3, a+4, a+1, a+2}; int **ptr = p; ptr++; printf("%d%d", ptr-p, **ptr); }The output of the program is ____________.

Let us trace the program step by step:

1. Array a contains five integers:

   • a[0] = 10, a[1] = 20, a[2] = 30, a[3] = 40, a[4] = 50

2. Array p is an array of pointers to int:

   • p[0] = a (points to a[0])

   • p[1] = a + 3 (points to a[3])

   • p[2] = a + 4 (points to a[4])

   • p[3] = a + 1 (points to a[1])

   • p[4] = a + 2 (points to a[2])

3. ptr is a pointer to pointer to int, initialized to p (i.e., &p[0]).

4. ptr++ increments ptr so that it points to p[1].

5. In printf("%d%d", ptr-p, **ptr):

   • ptr - p: Pointer subtraction gives the difference in elements, which is $1 - 0 = 1$.

   • **ptr: *ptr evaluates to p[1] (which is a + 3), and *(*ptr) dereferences that pointer to get a[3] = 40.

Printing %d%d without spaces between them outputs 140.