Consider the following C function in which size is the number of elements in the array E:int MyX(int *E, unsigned int size) { int Y = 0; int Z; int i, j, k; for(i = 0; i < size; i++) Y = Y + E[i]; for(i = 0; i < size; i++) for(j = i; j < size; j++) { Z = 0; for(k = i; k <= j; k++) Z = Z + E[k]; if (Z > Y) Y = Z; } return Y; }The value returned by the function MyX is the

Let us trace the given function:

1. The first for loop calculates the sum of all elements of array E and stores it in Y:

   $$Y = \sum_{m=0}^{\text{size}-1} E[m]$$

2. The nested loops iterate over all possible sub-arrays of array E starting at index i and ending at index j (where $0 \le i \le j < \text{size}$):

   • The innermost loop calculates $Z = \sum_{k=i}^j E[k]$, which is the sum of elements in the sub-array $E[i \dots j]$.

   • If $Z > Y$, then $Y$ is updated with $Z$.

3. Thus, $Y$ is updated whenever a sub-array sum exceeds the current maximum found so far (initialized to the total array sum).

Therefore, the function returns the maximum possible sum of elements in any sub-array of array E.

Hence, the correct option is (A).