Consider the following ANSI C program. #include int main() int arr[4][5]; int i, j; for (i=0; i What is the output of the above program? A) 14 B) 20 C) 24 D) 30

Official answer: C) 24. Explanation: The 2D array `arr[4][5]` has 4 rows and 5 columns, stored sequentially in row-major order in memory. The nested loops initialize each element `arr[i][j]` to 10 i + j: - Row 0: `arr[0][0]` to `arr[0][4]` have values 0, 1, 2, 3, 4 - Row 1: `arr[1][0]` to `arr[1][4]` have values 10, 11, 12, 13, 14 - Row 2: `arr[2][0]` to `arr[2][4]` have values 20, 21, 22, 23, 24 - Row 3: `arr[3][0]` to `arr[3][4]` have values 30, 31, 32, 33, 34 `arr[1]` decays to a pointer to the first element of the second row, i.e., `&arr[1][0]` (of type `int *`). Pointer arithmetic `arr[1] + 9` advances the pointer by 9 `int` elements starting from `arr[1][0]`: - 9 elements ahead from `arr[1][0]` corresponds to index: (1 5 + 0) + 9 = 14 in flat 1D indexing. - Converting linear index 14 back to 2D coordinates for an array with 5 columns: Row = 14 / 5 = 2 Column = 14 5 = 4 Thus, `*(arr[1] + 9)` accesses `arr[2][4]`. The value stored at `arr[2][4]` is: 10 2 + 4 = 24 Hence, the correct option is C.

Programming and Data Structures · Programming in C

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GATE CSE 2021 Set 2 Q10 · MCQ · 1 mark

Consider the following ANSI C program. `#include <stdio.h> int main(){ int arr[4][5]; int i, j; for (i=0; i<4; i++){ for (j=0; j<5; j++){ arr[i][j] = 10i + j; } } printf("%d", (arr[1] + 9)); return 0; }` What is the output of the above program?

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Programming in C

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In GATE CS, Programming in C is tested extensively through rigorous code tracing, pointer mechanics, and fundamental semantics rather than high-level syntax trivia. Questions emphasize pointer arithmetic and multidimensional array decay, storage classes (especially static local variables), evaluation order, side effects of increment/decrement operators, parameter passing mechanisms (pass-by-value vs pass-by-reference), and recursive program state tracking. The topic features a nearly balanced split between NAT and MCQ items across 1-mark and 2-mark categories, demanding precise, bug-free execution traces without a compiler.

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Programming and Data Structures · Programming in C

Official IIT answer key · IIT Bombay · Audited Aug 2026

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GATE CSE 2021 Set 2 Q10 · MCQ · 1 mark

Consider the following ANSI C program. `#include <stdio.h> int main(){ int arr[4][5]; int i, j; for (i=0; i<4; i++){ for (j=0; j<5; j++){ arr[i][j] = 10i + j; } } printf("%d", (arr[1] + 9)); return 0; }` What is the output of the above program?

Select an option to check

Key concept

Programming in C

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Examiner trap & misconception

Topic notes

How GATE tests Programming in C

Full Programming in C guide →

More on Programming in C

All 74 questions on Programming in C →

Independent practice explanation verified by the GateAI team. GATE is conducted by the IITs; question text follows the official paper.

Consider the following ANSI C program. `#include <stdio.h> int main(){ int arr[4][5]; int i, j; for (i=0; i<4; i++){ for (j=0; j<5; j++){ arr[i][j] = 10i + j; } } printf("%d", (arr[1] + 9)); return 0; }` What is the output of the above program?

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Consider the following ANSI C program. `#include <stdio.h> int main(){ int arr[4][5]; int i, j; for (i=0; i<4; i++){ for (j=0; j<5; j++){ arr[i][j] = 10i + j; } } printf("%d", (arr[1] + 9)); return 0; }` What is the output of the above program?

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Consider the following ANSI C program. #include <stdio.h> int main(){ int arr[4][5]; int i, j; for (i=0; i<4; i++){ for (j=0; j<5; j++){ arr[i][j] = 10*i + j; } } printf("%d", *(arr[1] + 9)); return 0; } What is the output of the above program?

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Consider the following ANSI C program. #include <stdio.h> int main(){ int arr[4][5]; int i, j; for (i=0; i<4; i++){ for (j=0; j<5; j++){ arr[i][j] = 10*i + j; } } printf("%d", *(arr[1] + 9)); return 0; } What is the output of the above program?

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Consider the following ANSI C program. `#include <stdio.h> int main(){ int arr[4][5]; int i, j; for (i=0; i<4; i++){ for (j=0; j<5; j++){ arr[i][j] = 10i + j; } } printf("%d", (arr[1] + 9)); return 0; }` What is the output of the above program?

Consider the following ANSI C program. `#include <stdio.h> int main(){ int arr[4][5]; int i, j; for (i=0; i<4; i++){ for (j=0; j<5; j++){ arr[i][j] = 10i + j; } } printf("%d", (arr[1] + 9)); return 0; }` What is the output of the above program?