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Boolean Algebra and Minimization

GATE CSE 2024 Set 2 · Q50

MSQ2 marksMedium

Time

Consider 4-variable functions f1,f2,f3,f4f1, f2, f3, f4 expressed in sum-of-minterms form as given below. f1=∑(0,2,3,5,7,8,11,13)f1 = \sum(0, 2, 3, 5, 7, 8, 11, 13) f2=∑(1,3,5,7,11,13,15)f2 = \sum(1, 3, 5, 7, 11, 13, 15) f3=∑(0,1,4,11)f3 = \sum(0, 1, 4, 11) f4=∑(0,2,6,13)f4 = \sum(0, 2, 6, 13) With respect to the circuit given above, which of the following options is/are CORRECT?

GATE CSE 2024 Set 2 Q50 diagram

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Solution

Step-by-step verified solution

Official answer: C) Y = Σ(0, 1, 2, 3, 4, 5, 6, 7); D) Y = Π(8, 9, 10, 11, 12, 13, 14, 15)

Boolean Algebra and Minimization

To determine the output function YY:

  1. Output of the AND gate: The AND operation corresponds to the intersection of minterm sets of f1f1 and f2f2:

    AND(f1,f2)=f1⋅f2={0,2,3,5,7,8,11,13}∩{1,3,5,7,11,13,15}={3,5,7,11,13}\text{AND}(f1, f2) = f1 \cdot f2 = \{0, 2, 3, 5, 7, 8, 11, 13\} \cap \{1, 3, 5, 7, 11, 13, 15\} = \{3, 5, 7, 11, 13\}
  2. Output of the OR gate: The OR operation corresponds to the union of minterm sets of f3f3 and f4f4:

    OR(f3,f4)=f3+f4={0,1,4,11}∪{0,2,6,13}={0,1,2,4,6,11,13}\text{OR}(f3, f4) = f3 + f4 = \{0, 1, 4, 11\} \cup \{0, 2, 6, 13\} = \{0, 1, 2, 4, 6, 11, 13\}
  3. Output of the XOR gate (YY): The XOR operation corresponds to the symmetric difference of the two sets (minterms present in one set but not both):

    Y=(f1⋅f2)⊕(f3+f4)Y = (f1 \cdot f2) \oplus (f3 + f4)
    • Common minterms: {11,13}\{11, 13\}

    • Minterms only in AND(f1,f2)\text{AND}(f1, f2): {3,5,7}\{3, 5, 7\}

    • Minterms only in OR(f3,f4)\text{OR}(f3, f4): {0,1,2,4,6}\{0, 1, 2, 4, 6\}

    Therefore, in sum-of-minterms form:

    Y=∑(0,1,2,3,4,5,6,7)Y = \sum(0, 1, 2, 3, 4, 5, 6, 7)
  4. Product-of-maxterms form: For a 4-variable Boolean function (minterms 0 through 15), the maxterms are the complement of the minterm set:

    Y=∏(8,9,10,11,12,13,14,15)Y = \prod(8, 9, 10, 11, 12, 13, 14, 15)

Hence, options C and D are correct.

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This Boolean Algebra and Minimization previous year question is Q50 of the GATE CSE 2024 Set 2 paper. Find more GATE CSE PYQs on Boolean Algebra and Minimization in Digital Logic, or browse all GATE CSE PYQs.

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Boolean Algebra and Minimization in GATE CSE

Boolean Algebra and Minimization has 36 GATE CSE PYQs across 23 papers from 2011 to 2026. 6 of them are 2-mark MSQs like this one, and GATE CSE 2024 Set 2 has 2.

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GateAI solution cardGATE CSE 2024 Set 2 · Q50 · MSQ

Consider 4-variable functions f1, f2, f3, f4 expressed in sum-of-minterms form as given below. f1 = Σ(0, 2, 3, 5, 7, 8, 11, 13) f2 = Σ(1, 3, 5, 7, 11, 13, 15) f3 = Σ(0, 1, 4, 11) f4 = Σ(0, 2, 6, 13) With respect to the circuit given above, which of the following options is/are CORRECT?

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Independent practice explanation verified by the GateAI team. GATE is conducted by the IITs; question text follows the official paper.