Let p denote "It rains" and q denote "The cricket match is played".
The conditional statement is: "If it rains, then the cricket match will not be played", which translates to p→egq.
For Inference I1:
eg q−Premise2:q(Thecricketmatchwasplayed)−Inference:
eg p$ (There was no rain)
By *Modus Tollens*, from p→egq and the negation of the consequent $eg(eg q) \equiv q,wecanvalidlyinferthenegationoftheantecedent
eg p.Thus,I_1$ is a valid/correct inference.
For Inference I2:
eg q−Premise2:
eg p(Itdidnotrain)−Inference:q$ (The cricket match was played)
Inferring q from egp is the fallacy of *Denying the Antecedent*. If it did not rain, the cricket match might or might not be played for other reasons. Thus, I2 is not a correct inference.
Therefore, I1 is correct but I2 is not a correct inference, which corresponds to option (B).