The value printed by the following program is _________ .void f(int* p, int m) { m = m + 5; *p = *p + m; return; } void main() { int i=5, j=10; f(&i, j); printf("%d", i+j); }

Let us trace the execution of the program step-by-step:

1. In main(), local variables are initialized as i = 5 and j = 10.

2. The function f(&i, j) is called:

   • p receives the address of i (&i), so *p directly modifies i in main() (pass-by-reference / pointer).

   • m receives the value 10 (pass-by-value).

3. Inside f():

   • m = m + 5; updates local variable m to $10 + 5 = 15$.

   • *p = *p + m; updates i to $5 + 15 = 20$.

   • The function returns, and the local copy m is discarded.

4. Back in main():

   • i has the updated value 20.

   • j remains unchanged as 10.

5. The expression i + j evaluates to $20 + 10 = 30$.

Hence, the printed value is 30.