Consider the following C Program.#include<stdio.h> #include<string.h> int main() { char* c = "GATECSIT2017"; char* p = c; printf("%d", (int)strlen(c+2[p]-6[p]-1)); return 0; }The output of the program is _________.

Let us analyze the pointer arithmetic and array indexing in C:

1. The string c is "GATECSIT2017" with 0-based indices:

   • c[0] = 'G'

   • c[1] = 'A'

   • c[2] = 'T'

   • c[3] = 'E'

   • c[4] = 'C'

   • c[5] = 'S'

   • c[6] = 'I'

   • c[7] = 'T'

   • c[8] = '2'

   • c[9] = '0'

   • c[10] = '1'

   • c[11] = '7'

   • c[12] = '\0'

2. The pointer $p$ points to the start of the string ($p = c$).

3. In C, 2[p] is equivalent to *(2 + p), which equals p[2] = 'T'. Similarly, 6[p] is equivalent to *(6 + p), which equals p[6] = 'I'.

4. Using their ASCII values:

   • $\text{ASCII}('T^{\prime}) = 84$

   • $\text{ASCII}('I^{\prime}) = 73$

   • Therefore, $2[p] - 6[p] = 'T^{\prime} - 'I^{\prime} = 84 - 73 = 11$.

5. The pointer expression inside strlen is:

   $$c + 2[p] - 6[p] - 1 = c + 11 - 1 = c + 10$$

6. The pointer c + 10 points to the substring "17".

7. strlen("17") evaluates to $2$.

Hence, the output printed is 2.