Consider the following C Program.#include<stdio.h> int main() { int m = 10; int n, n1; n = ++m; n1 = m++; n--; --n1; n -= n1; printf("%d", n); return 0; }The output of the program is _________.

Let us trace the execution of the program step by step:

1. int m = 10;

   • Variable $m$ is initialized to $10$.

2. n = ++m;

   • Pre-increment operator: $m$ is incremented first, so $m = 11$.

   • Then $n$ is assigned the value of $m$, so $n = 11$.

3. n1 = m++;

   • Post-increment operator: $n1$ receives the current value of $m$, so $n1 = 11$.

   • Then $m$ is incremented, so $m = 12$.

4. n--;

   • Post-decrement: $n$ is decremented by $1$, so $n = 10$.

5. --n1;

   • Pre-decrement: $n1$ is decremented by $1$, so $n1 = 10$.

6. n -= n1;

   • Compound assignment: $n = n - n1 = 10 - 10 = 0$.

7. printf("%d", n); prints the value of $n$, which is 0.