The integer value printed by the ANSI-C program given below is ________.#include<stdio.h> int funcp(){ static int x = 1; x++; return x; } int main(){ int x,y; x = funcp(); y = funcp()+x; printf("%d ", (x+y)); return 0; }

Let us trace the execution of the program step by step:

1. Inside funcp(), the variable x is declared as static int x = 1;. A static local variable retains its value between successive function calls and is initialized only once.

2. In main(), local variables x and y are declared.

3. The statement x = funcp(); executes:

   • Inside funcp(), x is incremented from $1$ to $2$ (x++).

   • funcp() returns $2$.

   • The local variable x in main is assigned the value $2$.

4. The statement y = funcp() + x; executes:

   • The second call to funcp() increments the static variable x from $2$ to $3$.

   • funcp() returns $3$.

   • The local variable x in main is still $2$.

   • Therefore, $y = 3 + 2 = 5$.

5. The statement `printf("%d

", (x+y));` prints:

Thus, the printed integer value is 7.