What is printed by the following ANSI C program?#include<stdio.h> int main(int argc, char *argv[]) { int x = 1, z[2] = {10, 11}; int *p = NULL; p = &x; *p = 10; p = &z[1]; *(&z[0] + 1) += 3; printf("%d, %d, %d ", x, z[0], z[1]); return 0; }

Let us trace the execution of the program step-by-step:

1. Initialization:

   • int x = 1; initializes variable x to 1.

   • z[2] = {10, 11}; initializes z[0] = 10 and z[1] = 11.

   • int *p = NULL; initializes pointer p to NULL.

2. Pointer operations on x:

   • p = &x; sets pointer p to store the address of x.

   • *p = 10; dereferences p and assigns 10 to x. Thus, x becomes 10.

3. Pointer arithmetic on array z:

   • p = &z[1]; updates p to point to z[1].

   • *(&z[0] + 1) += 3;:

     • &z[0] is the address of z[0].

     • Adding 1 advances the pointer by sizeof(int) bytes, pointing to &z[1].

     • Dereferencing *(&z[0] + 1) accesses z[1].

     • += 3 increases the value of z[1] from 11 to $11 + 3 = 14$.

   • z[0] remains unchanged as 10.

4. Output:

   • `printf("%d, %d, %d

", x, z[0], z[1]); prints 10, 10, 14`.

Hence, the correct option is (D).