The distance covered is given by the integral of velocity with respect to time:
S=∫020v(t)dt The motorbike starts from rest, so at t0=0, v0=0. The data points with equal step size h=2 minutes are:
t0=0,v0=0
t1=2,v1=10
t2=4,v2=18
t3=6,v3=25
t4=8,v4=29
t5=10,v5=32
t6=12,v6=20
t7=14,v7=11
t8=16,v8=5
t9=18,v9=2
t10=20,v10=0
Using Simpson's 1/3rd rule with n=10 (an even number of intervals):
S=3h[(v0+v10)+4(v1+v3+v5+v7+v9)+2(v2+v4+v6+v8)] Sum of odd-indexed terms:
∑vodd=10+25+32+11+2=80 Sum of even-indexed terms (excluding boundaries):
∑veven=18+29+20+5=72 Substituting these values into the formula:
S=32[(0+0)+4(80)+2(72)]=32[320+144]=32×464=3928≈309.33 km Rounding to two decimal places, the distance is 309.33 km (official acceptable range: 308 to 310).