Consider the following snippet of a C program. Assume that swap (&x, &y) exchanges the contents of x and y.int main() { int array[] = {3, 5, 1, 4, 6, 2}; int done = 0; int i; while (done == 0) { done = 1; for (i=0; i<=4; i++) { if (array[i] < array[i+1]) { swap(&array[i], &array[i+1]); done = 0; } } for (i=5; i>=1; i--) { if (array[i] > array[i-1]) { swap(&array[i], &array[i-1]); done = 0; } } } printf("%d", array[3]); }The output of the program is __________.

The algorithm shown is a bidirectional bubble sort (cocktail shaker sort) sorting the array in descending order.

1. Initial Array:

   $$\text{array} = [3, 5, 1, 4, 6, 2]$$

2. First pass of while (done == 0):

   • done is set to $1$.

   • Forward loop (i = 0 to 4): Swaps adjacent elements if $\text{array}[i] < \text{array}[i+1]$:

     • $i=0$: $3 < 5 \implies \text{swap} \implies [5, 3, 1, 4, 6, 2]$, done = 0

     • $i=1$: $3 < 1$ (False)

     • $i=2$: $1 < 4 \implies \text{swap} \implies [5, 3, 4, 1, 6, 2]$, done = 0

     • $i=3$: $1 < 6 \implies \text{swap} \implies [5, 3, 4, 6, 1, 2]$, done = 0

     • $i=4$: $1 < 2 \implies \text{swap} \implies [5, 3, 4, 6, 2, 1]$, done = 0

   • Backward loop (i = 5 down to 1): Swaps adjacent elements if $\text{array}[i] > \text{array}[i-1]$:

     • $i=5$: $1 > 2$ (False)

     • $i=4$: $2 > 6$ (False)

     • $i=3$: $6 > 4 \implies \text{swap} \implies [5, 3, 6, 4, 2, 1]$, done = 0

     • $i=2$: $6 > 3 \implies \text{swap} \implies [5, 6, 3, 4, 2, 1]$, done = 0

     • $i=1$: $6 > 5 \implies \text{swap} \implies [6, 5, 3, 4, 2, 1]$, done = 0

3. Second pass of while (done == 0):

   • done is set to $1$.

   • Forward loop (i = 0 to 4):

     • $i=0$: $6 < 5$ (False)

     • $i=1$: $5 < 3$ (False)

     • $i=2$: $3 < 4 \implies \text{swap} \implies [6, 5, 4, 3, 2, 1]$, done = 0

     • $i=3$: $3 < 2$ (False)

     • $i=4$: $2 < 1$ (False)

   • Backward loop (i = 5 down to 1):

     • No elements satisfy $\text{array}[i] > \text{array}[i-1]$.

4. Third pass:

   • No swaps occur in either loop, so done remains $1$ and the while loop terminates.

5. Output: The sorted array in descending order is $[6, 5, 4, 3, 2, 1]$. The element at index $3$ is:

   $$\text{array}[3] = 3$$

Thus, the program prints 3.