Consider the following C program:#include <stdio.h> int main() { int a; int arr[5] = {30,50,10}; int *ptr; ptr = &arr[0] + 1; a = *ptr; (*ptr)++; ptr++; printf("%d", a + (*ptr) + arr[1]); return 0; }The output of the above program is ________. (Answer in integer)

Let us trace the execution of the program step by step:

1. Array Initialization:int arr[5] = {30, 50, 10}; initializes the array with:

   • arr[0] = 30

   • arr[1] = 50

   • arr[2] = 10

   • arr[3] = 0

   • arr[4] = 0

2. Pointer Initialization:ptr = &arr[0] + 1; points ptr to arr[1] (the address of the element at index 1).

3. Assignment to $a$:a = *ptr; assigns the value of *ptr (which is arr[1] = 50) to a. Thus, $a = 50$.

4. Incrementing Value:(*ptr)++; increments the value stored at the address pointed to by ptr. Since ptr points to arr[1], the value of arr[1] becomes $50 + 1 = 51$.

5. Pointer Increment:ptr++; increments the pointer itself, so ptr now points to arr[2]. Therefore, *ptr is now arr[2] = 10.

6. Printing the Result: The expression to evaluate is a + (*ptr) + arr[1]:

   $$\text{Value} = 50 + 10 + 51 = 111$$

Thus, the output of the program is 111.