Consider the following C program:#include <stdio.h> int g(int n) { return (n+10); } int f(int n) { return g(n*2); } int main() { int sum, n; sum=0; for (n=1; n<3; n++) sum += g(f(n)); printf ("%d", sum); return 0; }The output of the given C program is ________. (Answer in integer)

Let us trace the functions step-by-step:

1. The function $g(n)$ returns $n + 10$.

2. The function $f(n)$ calls $g(2n)$, which evaluates to:

   $$f(n) = 2n + 10$$

3. The expression $g(f(n))$ evaluates to:

   $$g(f(n)) = f(n) + 10 = (2n + 10) + 10 = 2n + 20$$

Now, trace the for loop in main() with initial sum = 0:

• Iteration 1 ($n = 1$):

  $$g(f(1)) = 2(1) + 20 = 22$$

  $$\text{sum} = 0 + 22 = 22$$

• Iteration 2 ($n = 2$):

  $$g(f(2)) = 2(2) + 20 = 24$$

  $$\text{sum} = 22 + 24 = 46$$

• Iteration 3 ($n = 3$): The condition $n < 3$ evaluates to false, and the loop terminates.

printf("%d", sum) prints 46.