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Combinational and Sequential Circuits

GATE CSE 2025 Set 2 · Q34

NAT1 markMedium

Time

In a 4-bit ripple counter, if the period of the waveform at the last flip-flop is 64 microseconds, then the frequency of the ripple counter in kHz is ________ . (Answer in integer)

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Official answer: 250

Combinational and Sequential Circuits

A 4-bit ripple counter uses 4 flip-flops connected in series, dividing the input clock frequency by 24=162^4 = 16.

Let:

  • TinT_{\text{in}} be the time period of the input clock

  • ToutT_{\text{out}} be the time period of the waveform at the last (4th) flip-flop

Since frequency is divided by 1616, the time period is multiplied by 1616:

Tout=16×TinT_{\text{out}} = 16 \times T_{\text{in}}

Given Tout=64 μsT_{\text{out}} = 64\ \mu\text{s}:

Tin=64 μs16=4 μsT_{\text{in}} = \frac{64\ \mu\text{s}}{16} = 4\ \mu\text{s}

The frequency of the ripple counter (input clock frequency finf_{\text{in}}) is:

fin=1Tin=14 μs=14×10−6 s=250×103 Hz=250 kHzf_{\text{in}} = \frac{1}{T_{\text{in}}} = \frac{1}{4\ \mu\text{s}} = \frac{1}{4 \times 10^{-6}\text{ s}} = 250 \times 10^3\text{ Hz} = 250\text{ kHz}

Thus, the answer is 250.

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This Combinational and Sequential Circuits previous year question is Q34 of the GATE CSE 2025 Set 2 paper. Find more GATE CSE PYQs on Combinational and Sequential Circuits in Digital Logic, or browse all GATE CSE PYQs.

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Combinational and Sequential Circuits has 32 GATE CSE PYQs across 22 papers from 2011 to 2026. 6 of them are 1-mark NAT questions like this one, and it is the only one in GATE CSE 2025 Set 2.

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In a 4-bit ripple counter, if the period of the waveform at the last flip-flop is 64 microseconds, then the frequency of the ripple counter in kHz is … (Answer in integer)

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