Consider the following instruction sequence where registers R1, R2 and R3 are general purpose and MEMORY[X] denotes the content at the memory location X. Assume that the content of the memory location 5000 is 10, and the content of the register R3 is 3000. The content of each of the memory locations from 3000 to 3010 is 50. The instruction sequence starts from the memory location 1000. All the numbers are in decimal format. Assume that the memory is byte addressable. After the execution of the program, the content of memory location 3010 is ___________.

Let's determine the memory addresses occupied by each instruction starting at address 1000:

• Address 1000 (size 4): MOV R1, (5000)$\rightarrow \text{R1} = \text{MEMORY}[5000] = 10$

• Address 1004 (size 4): MOV R2, (R3)$\rightarrow \text{R2} = \text{MEMORY}[\text{R3}]$

• Address 1008 (size 2): ADD R2, R1$\rightarrow \text{R2} = \text{R1} + \text{R2}$

• Address 1010 (size 4): MOV (R3), R2$\rightarrow \text{MEMORY}[\text{R3}] = \text{R2}$

• Address 1014 (size 2): INC R3$\rightarrow \text{R3} = \text{R3} + 1$

• Address 1016 (size 2): DEC R1$\rightarrow \text{R1} = \text{R1} - 1$

• Address 1018 (size 2): BNZ 1004 $\rightarrow$ branches back to address 1004 if $\text{R1} \neq 0$

• Address 1020 (size 1): HALT

Tracing the loop iterations:

• Initially, $\text{R1} = 10$, $\text{R3} = 3000$.

• Iteration 1: $\text{MEMORY}[3000]$ is updated to $50 + 10 = 60$; $\text{R3}$ becomes $3001$, $\text{R1}$ becomes $9$.

• Iteration 2: $\text{MEMORY}[3001]$ is updated to $50 + 9 = 59$; $\text{R3}$ becomes $3002$, $\text{R1}$ becomes $8$.

• ...

• Iteration 10: $\text{MEMORY}[3009]$ is updated to $50 + 1 = 51$; $\text{R3}$ becomes $3010$, $\text{R1}$ becomes $0$.

When $\text{R1} = 0$, the condition BNZ 1004 evaluates to false and the loop terminates. The instruction at memory location 3010 is never updated by the loop, so its content remains unmodified at 50.