The stage delays in a 4-stage pipeline are 800, 500, 400 and 300 picoseconds. The first stage (with delay 800 picoseconds) is replaced with a functionally equivalent design involving two stages with respective delays 600 and 350 picoseconds. The throughput increase of the pipeline is _________ percent.

Original Pipeline:

• Number of stages = 4

• Stage delays = $800\text{ ps}, 500\text{ ps}, 400\text{ ps}, 300\text{ ps}$

• Cycle time of the original pipeline ($T_1$):

  $$T_1 = \max(800, 500, 400, 300) = 800\text{ ps}$$

• Original throughput ($\text{Throughput}_1$):

  $$\text{Throughput}_1 = \frac{1}{T_1} = \frac{1}{800\text{ ps}}$$

Modified Pipeline:

• The 800 ps stage is split into two stages of 600 ps and 350 ps.

• Stage delays = $600\text{ ps}, 350\text{ ps}, 500\text{ ps}, 400\text{ ps}, 300\text{ ps}$

• Cycle time of the new pipeline ($T_2$):

  $$T_2 = \max(600, 350, 500, 400, 300) = 600\text{ ps}$$

• New throughput ($\text{Throughput}_2$):

  $$\text{Throughput}_2 = \frac{1}{T_2} = \frac{1}{600\text{ ps}}$$

Percentage Increase in Throughput: